(Almost) Impossible Integrals, Sums, and Series (Problem Books in Mathematics)

(Almost) Impossible Integrals, Sums, and Series (Problem Books in Mathematics)

Matematika tolong di jawab dengan caranya​

tolong di jawab dengan caranya​

[tex]2 \frac{1}{3} \div \frac{7}{8} \times 2.75[/tex]

[tex] = \frac{(2 \times 3 + 1)}{3 \times 7} \times 2.75[/tex]

[tex] = \frac{(6 + 1) \times 8}{3 \times 7} \times 2.75[/tex]

[tex] = \frac{7 \times 8}{3 \times 7} \times 2.75[/tex]

[tex] = \frac{56}{21} \times 2.75[/tex]

[tex] = \frac{8}{3} \times 2.75[/tex]

[tex] = \frac{8}{3} \times ( \frac{11}{4} )[/tex]

[tex] = \frac{8 \times 11}{3 \times 4} [/tex]

[tex] = \frac{88}{12} [/tex]

[tex] = \frac{22}{3} [/tex]

[tex] = 7 \frac{1}{3} [/tex]

Kesimpulan hasilnya adalah : c. 7 1/3

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